9x^2-26x-140=0

Solution for 9x^2-26x-140=0 equation:

9x^2-26x-140=0

a = 9; b = -26; c = -140;
Δ = b2-4ac
Δ = -262-4·9·(-140)
Δ = 5716
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5716}=\sqrt{4*1429}=\sqrt{4}*\sqrt{1429}=2\sqrt{1429}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-2\sqrt{1429}}{2*9}=\frac{26-2\sqrt{1429}}{18}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+2\sqrt{1429}}{2*9}=\frac{26+2\sqrt{1429}}{18}
$